If $19.7 \ kg$ of gold is confiscated from a thief,how many atoms of gold were confiscated from him? $(Au = 197 \ g/mol)$
- A$6.022 \times 10^{24}$
- B$6.022 \times 10^{23}$
- C$6.022 \times 10^{25}$
- D$6.022 \times 10^{21}$
Explore More
Similar Questions
Number of atoms in $11.2 \, L$ of $CO_2$ at $NTP$ is .............. $N_A$
Medium
View Solution$6.02 \times 10^{20}$ molecules of urea are present in $100 \ mL$ of its solution. The concentration of solution is $.... M$.
DifficultNEET 2013
View SolutionFrom $392 \, mg$ of $H_2SO_4$,$1.204 \times 10^{21}$ molecules are removed. How many moles of $H_2SO_4$ are left?
Difficult
View SolutionThe number of water molecules present in a drop of water (volume $0.0018 \ mL$) at room temperature is
Difficult
View SolutionWhat is the approximate weight of one molecule of methane $(CH_4)$?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo