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(C) The chemical equation is: $C_7H_{14}(\ell) ightarrow C_7H_8(\ell) + 3H_2(g)$.Calculate the molar masses:$M(C_7H_{14}) = (7 	imes 12) + (14 	im

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(C) The chemical equation is: $C_7H_{14}(\ell) ightarrow C_7H_8(\ell) + 3H_2(g)$.Calculate the molar masses:$M(C_7H_{14}) = (7 	imes 12) + (14 	imes 1) = 84 + 14 = 98 \ g/mol$.$M(C_7H_8) = (7 	imes 12) + (8 	imes 1) = 84 + 8 = 92 \ g/mol$.Since $C_7H_{14}$ and $C_7H_8$ are liquids,the initial weight of the liquid is $98 \ g$ and the final weight of the liquid is $92 \ g$.The decrease in the weight of the liquid is $98 \ g - 92 \ g = 6 \ g$.The percentage decrease in the weight of the liquid is calculated as:$	ext{Percentage decrease} = \frac{	ext{Decrease in weight}}{	ext{Initial weight}} 	imes 100$$	ext{Percentage decrease} = \frac{6}{98} 	imes 100 \approx 6.12\%$.

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