What is the number of atoms present in 16 g | vedclass

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(A) The molar mass of $O_2$ is $32 \ g/mol$. Number of moles of $O_2 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{16 \ g}{32 \ g/mol} = 0.5 \

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$6.02 	imes 10^{23}$

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(A) The molar mass of $O_2$ is $32 \ g/mol$. Number of moles of $O_2 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{16 \ g}{32 \ g/mol} = 0.5 \ mol$. Number of molecules of $O_2 = 	ext{moles} 	imes N_A = 0.5 	imes 6.022 	imes 10^{23} = 3.011 	imes 10^{23}$ molecules. Since each $O_2$ molecule contains $2$ atoms of oxygen,the total number of atoms $= 2 	imes (3.011 	imes 10^{23}) = 6.022 	imes 10^{23}$ atoms.

What is the number of atoms present in $16 \ g$ of oxygen gas $(O_2)$?

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