In a solution of a solute in benzene with a m | vedclass

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Question

(B) solution with molality $x \ m$ means $x \ mol$ of solute is present in $1000 \ g$ of solvent (benzene).Moles of solute $= x$Moles of benzene $= \f

Vedclass · Accepted Answer

$3.2$

Vedclass · Answer

(B) solution with molality $x \ m$ means $x \ mol$ of solute is present in $1000 \ g$ of solvent (benzene).Moles of solute $= x$Moles of benzene $= \frac{1000}{78} \approx 12.82 \ mol$ (Molar mass of benzene $= 78 \ g \ mol^{-1}$).Mole fraction of solute $(X_{solute}) = 0.2$.Formula for mole fraction: $X_{solute} = \frac{n_{solute}}{n_{solute} + n_{solvent}}$.$0.2 = \frac{x}{x + 12.82}$.$0.2(x + 12.82) = x$.$0.2x + 2.564 = x$.$0.8x = 2.564$.$x = \frac{2.564}{0.8} = 3.205 \approx 3.2$.

In a solution of a solute in benzene with a molality of $x \ m$,the mole fraction of the solute is $0.2$. The value of $x$ is ...... .

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