How many atoms are contained in 5.6 L of oxy | vedclass

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(B) At $STP$,$1 \ 	ext{mole}$ of any gas occupies $22.4 \ L$. Number of moles of $O_2 = \frac{5.6 \ L}{22.4 \ L/mol} = 0.25 \ 	ext{mol}$. Number of

Vedclass · Accepted Answer

$3.01 	imes 10^{23} \ 	ext{atoms}$

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(B) At $STP$,$1 \ 	ext{mole}$ of any gas occupies $22.4 \ L$. Number of moles of $O_2 = \frac{5.6 \ L}{22.4 \ L/mol} = 0.25 \ 	ext{mol}$. Number of molecules of $O_2 = 0.25 	imes 6.022 	imes 10^{23} = 1.5055 	imes 10^{23} \ 	ext{molecules}$. Since each $O_2$ molecule contains $2$ oxygen atoms,the number of atoms $= 2 	imes 1.5055 	imes 10^{23} = 3.011 	imes 10^{23} \ 	ext{atoms}$.

How many atoms are contained in $5.6 \ L$ of oxygen gas at $STP$?

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