How many moles of lead chloride will be produ | vedclass

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(B) The balanced chemical equation is: $PbO + 2HCl \rightarrow PbCl_2 + H_2O$Calculate the moles of reactants:Moles of $PbO = \frac{6.5 \ g}{223.2 \ g

Vedclass · Accepted Answer

$0.029$

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(B) The balanced chemical equation is: $PbO + 2HCl ightarrow PbCl_2 + H_2O$Calculate the moles of reactants:Moles of $PbO = \frac{6.5 \ g}{223.2 \ g/mol} \approx 0.029 \ mol$Moles of $HCl = \frac{3.2 \ g}{36.5 \ g/mol} \approx 0.0876 \ mol$According to the stoichiometry,$1 \ mol$ of $PbO$ reacts with $2 \ mol$ of $HCl$.For $0.029 \ mol$ of $PbO$,we need $0.029 	imes 2 = 0.058 \ mol$ of $HCl$.Since we have $0.0876 \ mol$ of $HCl$ (which is more than $0.058 \ mol$),$PbO$ is the limiting reagent.Therefore,the moles of $PbCl_2$ produced will be equal to the moles of $PbO$ consumed,which is $0.029 \ mol$.

How many moles of lead chloride will be produced by the reaction of $6.5 \ g$ of $PbO$ and $3.2 \ g$ of $HCl$?

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