If an LPG cylinder contains a mixture of buta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The combustion reaction for butane $(C_4H_{10})$ is: $C_4H_{10} + \frac{13}{2} O_2 	o 4CO_2 + 5H_2O$ The molar mass of butane is $58 \ g/mol$. Fo

Vedclass · Accepted Answer

$3.58$

Vedclass · Answer

(D) The combustion reaction for butane $(C_4H_{10})$ is: $C_4H_{10} + \frac{13}{2} O_2 	o 4CO_2 + 5H_2O$ The molar mass of butane is $58 \ g/mol$. For $1 \ kg$ $(1000 \ g)$ of butane,the number of moles is $n = \frac{1000}{58} \ mol$. According to the stoichiometry,$1 \ mol$ of $C_4H_{10}$ requires $\frac{13}{2} \ mol$ of $O_2$. So,moles of $O_2$ required = $\frac{13}{2} 	imes \frac{1000}{58} \ mol$. Mass of $O_2$ required = $\frac{13}{2} 	imes \frac{1000}{58} 	imes 32 \ g$. Mass of $O_2$ = $3586.2 \ g \approx 3.58 \ kg$.

If an $LPG$ cylinder contains a mixture of butane and isobutane,what is the amount of oxygen required for the combustion of $1 \ kg$ of this mixture in $kg$?

Similar Questions

$5.75 \ mg$ of sodium vapour is converted to sodium ion. If the ionisation energy of sodium is $490 \ kJ \ mol^{-1}$ and atomic weight is $23 \ g \ mol^{-1}$,the amount of energy needed for this conversion will be (in $kJ$)

The conversion of oxygen to ozone occurs to the extent of $15\%$ only. The mass of ozone that can be prepared from $67.2 \ L$ of oxygen at $1 \ atm$ and $273 \ K$ will be ............ $g$.

If $5.85 \ g$ of sodium chloride is added to water to make a $500 \ mL$ solution,what is the molarity of the sodium chloride solution (in $M$)? (Molar mass $= 58.5 \ g/mol$)

The chloride of a metal has the formula $MCl_3$. The formula of its phosphate will be

How many moles of ethene are required to prepare $6.0 \ g$ of ethane by the hydrogenation process (in $mole$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module