Carbon and oxygen form two known compounds. O | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the first compound,$C = 42.9\%$ and $O = 57.1\%$. Ratio of $C:O = \frac{42.9}{57.1} = 0.751:1$. In the second compound,$C = 27.3\%$ and $O = 72

Vedclass · Accepted Answer

Multiple Proportions

Vedclass · Answer

(B) In the first compound,$C = 42.9\%$ and $O = 57.1\%$. Ratio of $C:O = \frac{42.9}{57.1} = 0.751:1$. In the second compound,$C = 27.3\%$ and $O = 72.7\%$. Ratio of $C:O = \frac{27.3}{72.7} = 0.376:1$. Comparing the ratio of $C$ for a fixed amount of $O$: Ratio $= 0.751 : 0.376 = 2 : 1$. Since the ratio is a simple whole number,this illustrates the Law of Multiple Proportions.

Carbon and oxygen form two known compounds. One compound contains $42.9\%$ carbon,while the other contains $27.3\%$ carbon. This illustrates the law of:

Similar Questions

Complete combustion of $0.66 \ g$ of a hydrocarbon gives $1.32 \ g$ of $CO_2$ and $2.7 \ g$ of water. The results of the given data follow the law of ...

After a chemical reaction,the total mass of reactants and products

Gay-Lussac's law of gaseous volumes is derived from $.......$.

Which of the following pairs of compounds cannot demonstrate the law of multiple proportions?

Which of the following examples illustrates the Law of Multiple Proportions?

Vedclass Test Series

Exam Paper Generator

Online Exam Module