The number of chlorine atoms in $1.98 \ g$ of $BaCl_2$ is ..... (Atomic weight of $Ba = 137$,$Cl = 35.5$)

  • A
    $\frac{N_A}{10}$
  • B
    $\frac{N_A}{50}$
  • C
    $\frac{N_A}{25}$
  • D
    $\frac{N_A}{15}$

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