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(C) Nitrogen gas exists as $N_2$ molecules. The molar mass of $N_2$ is $28 \ g/mol$ and the atomic mass of $N$ is $14 \ g/mol$. Number of molecules in

Vedclass · Accepted Answer

$\frac{N_A}{28} 	ext{ molecules}, \frac{N_A}{14} 	ext{ atoms}$

Vedclass · Answer

(C) Nitrogen gas exists as $N_2$ molecules. The molar mass of $N_2$ is $28 \ g/mol$ and the atomic mass of $N$ is $14 \ g/mol$. Number of molecules in $1 \ g$ of $N_2$: $	ext{Moles} = \frac{	ext{mass}}{	ext{molar mass}} = \frac{1}{28} \ mol$. $	ext{Number of molecules} = 	ext{moles} 	imes N_A = \frac{N_A}{28} 	ext{ molecules}$. Number of atoms in $1 \ g$ of nitrogen: $	ext{Moles of atoms} = \frac{	ext{mass}}{	ext{atomic mass}} = \frac{1}{14} \ mol$. $	ext{Number of atoms} = 	ext{moles} 	imes N_A = \frac{N_A}{14} 	ext{ atoms}$.

The number of molecules and the number of atoms present in $1 \ g$ of nitrogen are respectively .....

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