What is the mass of oxygen in 32.2 g of Na_2 | vedclass

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(B) The molar mass of $Na_2SO_4 \cdot 10H_2O$ is $(2 	imes 23) + 32 + (4 	imes 16) + 10 	imes (2 	imes 1 + 16) = 46 + 32 + 64 + 180 = 322 \ g/mol$

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$22.4$

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(B) The molar mass of $Na_2SO_4 \cdot 10H_2O$ is $(2 	imes 23) + 32 + (4 	imes 16) + 10 	imes (2 	imes 1 + 16) = 46 + 32 + 64 + 180 = 322 \ g/mol$. Number of moles of $Na_2SO_4 \cdot 10H_2O = \frac{32.2 \ g}{322 \ g/mol} = 0.1 \ mol$. In one molecule of $Na_2SO_4 \cdot 10H_2O$,there are $4$ (in $SO_4$) $+ 10$ (in $10H_2O$) $= 14$ oxygen atoms. Total moles of oxygen atoms $= 14 	imes 0.1 = 1.4 \ mol$. Mass of oxygen $= 1.4 \ mol 	imes 16 \ g/mol = 22.4 \ g$.

What is the mass of oxygen in $32.2 \ g$ of $Na_2SO_4 \cdot 10H_2O$ (in $g$)?

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