Heating 1.520 g of a metal hydroxide gives 0 | vedclass

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(D) Let the equivalent weight of the metal be $x$.The equivalent weight of $OH^-$ is $17$ and the equivalent weight of $O^{2-}$ is $8$.According to th

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$9$

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(D) Let the equivalent weight of the metal be $x$.The equivalent weight of $OH^-$ is $17$ and the equivalent weight of $O^{2-}$ is $8$.According to the law of equivalence:$\frac{	ext{Mass of metal hydroxide}}{	ext{Mass of metal oxide}} = \frac{	ext{Equivalent weight of metal} + 	ext{Equivalent weight of } OH^-}{	ext{Equivalent weight of metal} + 	ext{Equivalent weight of } O^{2-}}$$\frac{1.520}{0.995} = \frac{x + 17}{x + 8}$$1.520(x + 8) = 0.995(x + 17)$$1.520x + 12.160 = 0.995x + 16.915$$1.520x - 0.995x = 16.915 - 12.160$$0.525x = 4.755$$x = \frac{4.755}{0.525} \approx 9.057 \approx 9$Thus,the equivalent weight of the metal is $9$.

Heating $1.520 \ g$ of a metal hydroxide gives $0.995 \ g$ of the metal oxide. Calculate the equivalent weight of the metal.

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