When $12 \ L$ of $H_2$ and $11.2 \ L$ of $Cl_2$ are mixed and allowed to react according to the equation $H_{2(g)} + Cl_{2(g)} \rightarrow 2HCl_{(g)}$,what is the final composition of the mixture?

  • A
    $24 \ L \ HCl_{(g)}$
  • B
    $0.8 \ L \ Cl_2$ and $20.8 \ L \ HCl_{(g)}$
  • C
    $0.8 \ L \ H_2$ and $22.4 \ L \ HCl_{(g)}$
  • D
    $22.4 \ L \ HCl_{(g)}$

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