(B) The formula for molarity $(M)$ is given by: $M = \frac{n}{V(L)}$First,calculate the number of moles $(n)$ of $NaNO_3$:$n = \frac{\text{mass}}{\tex

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(B) The formula for molarity $(M)$ is given by: $M = \frac{n}{V(L)}$First,calculate the number of moles $(n)$ of $NaNO_3$:$n = \frac{\text{mass}}{\text{molar mass}} = \frac{0.38 \ g}{85 \ g/mol} \approx 0.00447 \ mol$Next,convert the volume $(V)$ from $mL$ to $L$:$V = 50.0 \ mL = 0.050 \ L$Now,calculate the molarity:$M = \frac{0.00447 \ mol}{0.050 \ L} = 0.0894 \ M = 8.94 \times 10^{-2} \ M$

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

Medium

$A$ sample of $NaNO_3$ weighing $0.38 \ g$ is placed in a $50.0 \ mL$ volumetric flask. The flask is filled to the mark with water. What is the molarity of the solution?

A
$5.25 \times 10^2 \ M$
B
$8.94 \times 10^{-2} \ M$
C
$7.75 \times 10^2 \ M$
D
$7.35 \times 10^{-2} \ M$

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Some Basic Concepts of Chemistry

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Chemical stoichiometry

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$A$ sample of $NaNO_3$ weighing $0.38 \ g$ is placed in a $50.0 \ mL$ volumetric flask. The flask is filled to the mark with water. What is the molarity of the solution?

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$A$ $300 \ mL$ bottle of soft drink has $0.2 \ M$ $CO_2$ dissolved in it. Assuming $CO_2$ behaves as an ideal gas,the volume of the dissolved $CO_2$ at $STP$ is $...... \ mL$. (Nearest integer) Given: At $STP$,molar volume of an ideal gas is $22.7 \ L \ mol^{-1}$.

One litre oxygen gas at $STP$ will weigh $.................. \ g$

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What is the weight of carbon in $kg$ required to produce $270 \ kg$ of aluminum from bauxite by the Hall-Heroult process?

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