How many moles and grams of sodium chloride a | vedclass

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(C) Given: Volume of solution $V = 200 \ cm^3 = 0.2 \ L$,Molarity $M = 0.2 \ M$.Formula: $	ext{Molarity} = \frac{	ext{Number of moles of solute}}{

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$0.04, 2.34 \ g$

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(C) Given: Volume of solution $V = 200 \ cm^3 = 0.2 \ L$,Molarity $M = 0.2 \ M$.Formula: $	ext{Molarity} = \frac{	ext{Number of moles of solute}}{	ext{Volume of solution in Liters}}$.Number of moles of $NaCl = 	ext{Molarity} 	imes 	ext{Volume in Liters} = 0.2 \ M 	imes 0.2 \ L = 0.04 \ 	ext{moles}$.Molar mass of $NaCl = 23 + 35.5 = 58.5 \ g/mol$.Mass of $NaCl = 	ext{Number of moles} 	imes 	ext{Molar mass} = 0.04 \ 	ext{mol} 	imes 58.5 \ g/mol = 2.34 \ g$.

How many moles and grams of sodium chloride are present in $200 \ cm^3$ of $0.2 \ M \ NaCl$ solution?

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