How many oxygen atoms are present in 4.4 g o | vedclass

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(C) The molar mass of $CO_2$ is $44 \ g/mol$. Number of moles of $CO_2 = \frac{4.4 \ g}{44 \ g/mol} = 0.1 \ mol$. Number of molecules of $CO_2 = 0.1 \

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$1.204 	imes 10^{23}$

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(C) The molar mass of $CO_2$ is $44 \ g/mol$. Number of moles of $CO_2 = \frac{4.4 \ g}{44 \ g/mol} = 0.1 \ mol$. Number of molecules of $CO_2 = 0.1 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{22} \ 	ext{molecules}$. Since each molecule of $CO_2$ contains $2$ oxygen atoms,Number of oxygen atoms = $2 	imes 6.022 	imes 10^{22} = 1.2044 	imes 10^{23} \ 	ext{atoms}$.

How many oxygen atoms are present in $4.4 \ g$ of $CO_2$?

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