What is the volume of 22.4 , L of water vapor | vedclass

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Question

(D) At $NTP$,$1 \, mole$ of any gas occupies $22.4 \, L$ volume. Given volume of water vapor $= 22.4 \, L$,which corresponds to $1 \, mole$ of $H_2O$.

Vedclass · Accepted Answer

$18 \, mL$

Vedclass · Answer

(D) At $NTP$,$1 \, mole$ of any gas occupies $22.4 \, L$ volume. Given volume of water vapor $= 22.4 \, L$,which corresponds to $1 \, mole$ of $H_2O$. The reaction for condensation is: $H_2O_{(g)} ightarrow H_2O_{(l)}$. $1 \, mole$ of $H_2O$ vapor produces $1 \, mole$ of liquid $H_2O$. The molar mass of $H_2O$ is $18 \, g/mol$. Mass of $1 \, mole$ of $H_2O = 18 \, g$. Density of liquid water is $1 \, g/mL$. Volume $= \frac{	ext{Mass}}{	ext{Density}} = \frac{18 \, g}{1 \, g/mL} = 18 \, mL$.

What is the volume of $22.4 \, L$ of water vapor at $NTP$ when it is condensed into liquid water?

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