When 1 , text{mol} of anhydrous salt AB is di | vedclass

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Question

(B) The enthalpy of solution of an anhydrous salt is given by the relation: $\Delta H_{	ext{sol(anhydrous)}} = \Delta H_{	ext{hydration}} + \Delta H

Vedclass · Accepted Answer

$8$

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(B) The enthalpy of solution of an anhydrous salt is given by the relation: $\Delta H_{	ext{sol(anhydrous)}} = \Delta H_{	ext{hydration}} + \Delta H_{	ext{sol(hydrated)}}$.Given: $\Delta H_{	ext{sol(anhydrous)}} = -21.0 \, J \, 	ext{mol}^{-1}$ (since heat is released,it is exothermic).Given: $\Delta H_{	ext{hydration}} = -29.4 \, J \, 	ext{mol}^{-1}$.Substituting the values: $-21.0 = -29.4 + \Delta H_{	ext{sol(hydrated)}}$.$\Delta H_{	ext{sol(hydrated)}} = -21.0 + 29.4 = +8.4 \, J \, 	ext{mol}^{-1}$.

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