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(A) For an adiabatic process,$q = 0$. According to the first law of thermodynamics,$\Delta U = q + w$. Since the gas is compressed,work is done on the

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Greater than the initial temperature

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(A) For an adiabatic process,$q = 0$. According to the first law of thermodynamics,$\Delta U = q + w$. Since the gas is compressed,work is done on the system,so $w > 0$. Therefore,$\Delta U > 0$,which means the internal energy of the system increases. Since internal energy is a function of temperature $(U \propto T)$,an increase in internal energy leads to an increase in temperature. Thus,the final temperature is greater than the initial temperature.

When a gas is compressed adiabatically and reversibly,the final temperature is.......

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