What is the change in entropy in $J \ K^{-1} \ mol^{-1}$ for the conversion of $1 \ mol$ of ice to water at $0 \, ^\circ C$? For the process $H_2O_{(s)} \rightarrow H_2O_{(l)}$ at $0 \, ^\circ C$,$\Delta H_{fus} = 6 \, kJ \ mol^{-1}$.

  • A
    $20.13$
  • B
    $2.013$
  • C
    $2.198$
  • D
    $21.98$

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$(ii)$ The unit of molar entropy is .......... .
$(iii)$ The process of conversion of graphite into diamond is of ........ type.

One mole of ice is converted into water at $1 \ atm$ and $273 \ K$. The entropies of $H_2O_{(s)}$ and $H_2O_{(\ell)}$ are $38.2$ and $60.01 \ J \ mol^{-1} \ K^{-1}$ respectively. The enthalpy change for the conversion is ...... $J \ mol^{-1}$.

Observe the following reactions:
$I$. $CaCO_{3(s)} \rightarrow CaO_{(s)} + CO_{2(g)}$
$II$. $Cl_{2(g)} \rightarrow 2 Cl_{(g)}$
$III$. $H_2O_{(l)} \rightarrow H_2O_{(s)}$
Identify the reactions in which entropy increases.

The unit of entropy is

The enthalpy change for the transition of liquid water to steam at $100\,^oC$ is $40.8\, kJ\, mol^{-1}$. The entropy change for this process is .... $J\, K^{-1}\, mol^{-1}$.

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