If a diploid cell has 20 text{ pg} of DNA aft | vedclass

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(C) $1$. In the $S$ phase,$DNA$ replication occurs,doubling the amount of $DNA$ in a cell.$2$. After the $S$ phase,the cell contains $20 	ext{ pg}$ o

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Haploid,$5 	ext{ pg } DNA$

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(C) $1$. In the $S$ phase,$DNA$ replication occurs,doubling the amount of $DNA$ in a cell.$2$. After the $S$ phase,the cell contains $20 	ext{ pg}$ of $DNA$ and is diploid $(2n)$.$3$. Meiosis-$I$ reduces the chromosome number by half,resulting in two haploid cells,each with $10 	ext{ pg}$ of $DNA$ (since each chromosome still consists of two sister chromatids).$4$. During Anaphase-$II$,the sister chromatids separate and move to opposite poles.$5$. After the completion of Meiosis-$II$,each daughter nucleus receives one set of chromosomes (haploid) and half the amount of $DNA$ present in the cell at the end of Meiosis-$I$.$6$. Therefore,each daughter nucleus will be haploid $(n)$ and contain $5 	ext{ pg}$ of $DNA$.

If a diploid cell has $20 \text{ pg}$ of $DNA$ after the $S$ phase,what will be the condition in each daughter nucleus after Anaphase-$II$?

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