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(C) The distance between genes is directly proportional to the percentage of recombination. $1$. Given distances: $A-D = 10$, $A-C = 3$, $C-D = 7$. Si

Vedclass · Accepted Answer

$BACD$

Vedclass · Answer

(C) The distance between genes is directly proportional to the percentage of recombination. $1$. Given distances: $A-D = 10$, $A-C = 3$, $C-D = 7$. Since $A-C + C-D = 3 + 7 = 10 = A-D$, the order must be $A-C-D$. $2$. Given distances: $A-B = 5$, $C-B = 8$. Since $A-C = 3$ and $A-B = 5$, and $C-B = 8$, the gene $B$ must be on the other side of $A$ relative to $C$. $3$. Checking the order $B-A-C-D$: - Distance $B-A = 5$ - Distance $A-C = 3$ - Distance $C-D = 7$ - Total distance $B-D = 5 + 3 + 7 = 15$. - Distance $B-C = B-A + A-C = 5 + 3 = 8$. This matches all given data. Thus, the correct order is $BACD$.

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