A human male is heterozygous for autosomal ge | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The genotype of the male is $AaBbX^hY$. Since the genes $A$ and $B$ are autosomal and heterozygous,and the hemophilia gene $h$ is $X$-linked,we de

Vedclass · Accepted Answer

$1/8$

Vedclass · Answer

(B) The genotype of the male is $AaBbX^hY$. Since the genes $A$ and $B$ are autosomal and heterozygous,and the hemophilia gene $h$ is $X$-linked,we determine the gamete formation using the principle of independent assortment. The possible gametes for the autosomal genes $AaBb$ are $AB, Ab, aB,$ and $ab$. Each occurs with a probability of $1/4$. The sex chromosomes are $X^h$ and $Y$. Each occurs with a probability of $1/2$. To get the combination $abh$,the sperm must carry the autosomal combination $ab$ and the $X^h$ chromosome. The probability of $ab$ is $1/4$. The probability of $X^h$ is $1/2$. Therefore,the probability of the sperm being $abh$ is $(1/4) 	imes (1/2) = 1/8$.

$A$ human male is heterozygous for autosomal genes $A$ and $B$ and is also hemophilic (gene $h$). What proportion of his sperm will contain the $abh$ gene combination?

Similar Questions

The probability of the genotype $TTrr$ in the $F_2$ generation of a dihybrid cross is:

What is the phenotypic ratio of a test cross in the $F_1$ generation of a dihybrid cross?

If the gametes of an individual are $RY$ and $Ry$ only,then the genotype of the same individual will be . . . . . . .

From a cross $AABb \times aaBb$,the genotypes $AaBB : AaBb : Aabb : aabb$ will be obtained in the following ratio:

How many types of gametes may be produced by genotype $D/d : E/e : F/f$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module