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(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of the dominant allele and $q$ i

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$0.09$

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(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of the dominant allele and $q$ is the frequency of the recessive allele.Given that the frequency of the dominant allele $p = 0.7$,we can calculate the frequency of the recessive allele $q$ as follows:$q = 1 - p = 1 - 0.7 = 0.3$.The frequency of the recessive phenotype in a population is represented by the Hardy-Weinberg equation term $q^2$ (homozygous recessive genotype).Therefore,the frequency of the recessive phenotype = $q^2 = (0.3)^2 = 0.09$.

In a random mating population,the frequency of the dominant allele is $0.7$. What will be the frequency of the recessive phenotype?

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