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(D) dihybrid heterozygote has the genotype $AaBb$. According to the law of independent assortment,the alleles of two different genes segregate indepen

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$4$ types and $1:1:1:1$ ratio

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(D) dihybrid heterozygote has the genotype $AaBb$. According to the law of independent assortment,the alleles of two different genes segregate independently during gamete formation. The possible gametes produced by $AaBb$ are $AB, Ab, aB,$ and $ab$. Thus,there are $4$ types of gametes produced. Since each type is produced with equal probability,the ratio of these gametes is $1:1:1:1$.

How many types of gametes and in what ratio will be produced by a dihybrid heterozygote?

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