Systolic blood pressure is higher than diasto | vedclass

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Question

(D) Systole refers to the contraction phase of the heart,specifically the ventricles. During ventricular systole,the heart muscle contracts,forcing bl

Vedclass · Accepted Answer

Blood is pumped into the arteries with force during systole.

Vedclass · Answer

(D) Systole refers to the contraction phase of the heart,specifically the ventricles. During ventricular systole,the heart muscle contracts,forcing blood out of the ventricles and into the arteries (like the aorta) under high pressure. This results in a peak pressure known as systolic blood pressure. Conversely,diastole is the relaxation phase where the heart fills with blood,resulting in a lower pressure known as diastolic blood pressure. Therefore,systolic pressure is higher because blood is actively and forcefully ejected into the arterial system.

Column $-I$	Column $-II$
$(a) \; P-$wave	$(i) \; \text{Depolarisation of ventricles}$
$(b) \; QRS$ complex	$(ii) \; \text{Repolarisation of ventricles}$
$(c) \; T-$wave	$(iii) \; \text{Coronary ischemia}$
$(d) \; \text{Reduction in the size of } T-$wave	$(iv) \; \text{Depolarisation of atria}$
	$(v) \; \text{Repolarisation of atria}$

List $I$	List $II$
$A$. $P$ wave	$I$. Heart muscles are electrically silent.
$B$. $QRS$ complex	$II$. Depolarisation of ventricles.
$C$. $T$ wave	$III$. Depolarisation of atria.
$D$. $T-P$ gap	$IV$. Repolarisation of ventricles.

Systolic blood pressure is higher than diastolic blood pressure because:

Similar Questions

Which of the following statements regarding blood pressure is correct?

In $ECG$,the $T$-wave represents:

The $T$-wave in a normal $ECG$ represents . . . . . . .

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