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(C) The torque $	au$ is defined as $	au = r 	imes F$. Since the force $F$ and the perpendicular distance $r$ from the axis of rotation to the line

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Greater in case $(b)$

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(C) The torque $	au$ is defined as $	au = r 	imes F$. Since the force $F$ and the perpendicular distance $r$ from the axis of rotation to the line of action of the force are the same in both cases,the torque $	au$ is equal for both $(a)$ and $(b)$.Using the relation $	au = I \alpha$,where $I$ is the moment of inertia and $\alpha$ is the angular acceleration,we have $\alpha = \frac{	au}{I}$.Since the torque $	au$ is constant,the angular acceleration $\alpha$ is inversely proportional to the moment of inertia $I$ $(\alpha \propto \frac{1}{I})$.In case $(b)$,the axis of rotation is closer to the center of mass compared to case $(a)$,resulting in a smaller moment of inertia $I$. Therefore,the angular acceleration $\alpha$ will be greater in case $(b)$.

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