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(D) Let the side of the square plate be $L$ and its mass be $M$. The center of mass of the original square is at the origin $(0,0)$.Let the four corne

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$IV$ quadrant

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(D) Let the side of the square plate be $L$ and its mass be $M$. The center of mass of the original square is at the origin $(0,0)$.Let the four corners be located at $(L/2, L/2)$,$(-L/2, L/2)$,$(-L/2, -L/2)$,and $(L/2, -L/2)$.Let the mass of each small removed square be $m$. If we remove squares $1, 2,$ and $3$ (assuming they are in the $I, II,$ and $III$ quadrants respectively),the remaining mass is concentrated in the $IV$ quadrant.The center of mass of the remaining system shifts towards the quadrant where the mass is still present.Since the mass is removed from the $I, II,$ and $III$ quadrants,the center of mass will shift into the $IV$ quadrant.

$A$ uniform square plate is shown in the figure. Four identical small squares are removed from its corners. If squares $1, 2,$ and $3$ are removed,where will the center of mass $(C.M.)$ be located?

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