The electronic configuration of the phosphide | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The atomic number of phosphorus $(P)$ is $15$. The phosphide ion $(P^{3-})$ is formed by gaining $3$ electrons,so it has $15 + 3 = 18$ electrons.I

Vedclass · Accepted Answer

Chloride ion $(Cl^-)$

Vedclass · Answer

(D) The atomic number of phosphorus $(P)$ is $15$. The phosphide ion $(P^{3-})$ is formed by gaining $3$ electrons,so it has $15 + 3 = 18$ electrons.Its electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^6$,which is the same as that of the noble gas Argon $(Ar)$.Among the given options,the chloride ion $(Cl^-)$ has an atomic number of $17$ and gains $1$ electron to have $17 + 1 = 18$ electrons.Thus,the electronic configuration of $P^{3-}$ ($18$ electrons) is similar to that of $Cl^-$ ($18$ electrons).

Column-$I$	Column-$II$
$(a)$ $4s$	$(p)$ Circular orbit around nucleus
$(b)$ $4p$	$(q)$ Non-directional orbital
$(c)$ $1s$	$(r)$ Angular momentum $= 2h/\pi$
$(d)$ $3d$	$(s)$ Radial node is zero

The electronic configuration of the phosphide ion $(P^{3-})$ is similar to which of the following?

Similar Questions

Match the columns and choose the correct option:

Column-$I$ Column-$II$

$(a)$ $4s$ $(p)$ Circular orbit around nucleus

$(b)$ $4p$ $(q)$ Non-directional orbital

$(c)$ $1s$ $(r)$ Angular momentum $= 2h/\pi$

$(d)$ $3d$ $(s)$ Radial node is zero

From the following sets of quantum numbers,which set is possible?

Identify the incorrect statement from the following.

When the $4d$ orbital is complete,the newly entering electron goes into which orbital?

Write about $p$-orbitals.

Vedclass Test Series

Exam Paper Generator

Online Exam Module