$PbF_4$ and $PbCl_4$ exist,while $PbBr_4$ and $PbI_4$ do not exist. This is due to:
- ALarge size of $Br$ and $I$
- BStrong oxidizing nature of $Pb^{4+}$
- CStrong reducing nature of $Pb^{4+}$
- DLow electronegativity of $Br^-$ and $I^-$
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Similar Questions
Which of the following elements forms oxides in all oxidation states from $+I$ to $+V$?
Medium
View SolutionIdentify the false statement about red phosphorus.
Easy
View Solution$NaH_2PO_4$ $\xrightarrow{230^\circ C}$ $Na_3P_3O_9$ $\xrightarrow{638^\circ C}$ $(NaPO_3)_n$ $\rightarrow D$ (glossy solid).
Compound $D$ is sodium hexametaphosphate,which is known as:
Compound $D$ is sodium hexametaphosphate,which is known as:
Easy
View SolutionWhich among the following oxoacids of phosphorus will have $P-O-P$ bonds?
$I$. $H_4P_2O_5$
$II$. $H_4P_2O_6$
$III$. $H_4P_2O_7$
$IV$. $(HPO_3)_3$
$I$. $H_4P_2O_5$
$II$. $H_4P_2O_6$
$III$. $H_4P_2O_7$
$IV$. $(HPO_3)_3$
The oxide of nitrogen formed by thermal decomposition of $NH_4NO_3$ is
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