Substance $X$ reacts with an aqueous solution of $NaOH$ to form $Y$ and releases $H_2$ gas. When an aqueous solution of $Y$ is heated at $323 \; K - 333 \; K$ and $CO_2$ gas is passed through it,it yields $Al_2O_3 \cdot xH_2O$ (often represented as $Al(OH)_3$) and $Z$. Heating $Z$ at $1200^{\circ}C$ produces $Al_2O_3$. Identify $X, Y,$ and $Z$.
- A$Al, AlCl_3, NaAlO_2$
- B$Zn, Na_2ZnO_2, Al(OH)_3$
- C$Al, Al(OH)_3, AlCl_3$
- D$Al, NaAlO_2, Al(OH)_3$
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Draw the structure of boric acid showing hydrogen bonding. Which species is present in water? What is the hybridization of boron in this species?
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Statement $I$: Aluminium is more electropositive than thallium as the standard electrode potential value of $E^\circ_{Al^{3+}/Al}$ is negative and $E^\circ_{Tl^{3+}/Tl}$ is positive.
Statement $II$: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason,boron forms covalent compounds only and aluminium forms $Al^{3+}$ ion.
Statement $I$: Aluminium is more electropositive than thallium as the standard electrode potential value of $E^\circ_{Al^{3+}/Al}$ is negative and $E^\circ_{Tl^{3+}/Tl}$ is positive.
Statement $II$: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason,boron forms covalent compounds only and aluminium forms $Al^{3+}$ ion.
Aluminium $(III)$ chloride forms a dimer because
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