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(B) The balanced chemical equation for aerobic respiration is: $C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + 686 \ kcal$ energy.$1$. Molar mass of

Vedclass · Accepted Answer

$264 \ gm$ of $CO_2$,$108 \ gm$ of $H_2O$ & $686 \ kcal$ energy

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(B) The balanced chemical equation for aerobic respiration is: $C_6H_{12}O_6 + 6O_2 ightarrow 6CO_2 + 6H_2O + 686 \ kcal$ energy.$1$. Molar mass of glucose $(C_6H_{12}O_6)$ = $(6 	imes 12) + (12 	imes 1) + (6 	imes 16) = 72 + 12 + 96 = 180 \ g/mol$.$2$. Molar mass of $6O_2$ = $6 	imes (2 	imes 16) = 6 	imes 32 = 192 \ g$.$3$. According to the equation,$180 \ g$ of glucose reacts with $192 \ g$ of oxygen to produce:- $6 	imes CO_2$ = $6 	imes (12 + 32) = 6 	imes 44 = 264 \ g$.- $6 	imes H_2O$ = $6 	imes (2 + 16) = 6 	imes 18 = 108 \ g$.- Energy released = $686 \ kcal$.Therefore,the correct option is $B$.

Column $A$	Column $B$
$A$. Molecular oxygen	$(i)$. $\alpha$-Ketoglutaric acid
$B$. Electron acceptor	$(ii)$. Hydrogen acceptor
$C$. Pyruvate dehydrogenase	$(iii)$. Cytochrome $c$
$D$. Decarboxylation	$(iv)$. Acetyl $CoA$

During the process of plant respiration,what is produced by $180 \ gm$ of glucose and $192 \ gm$ of oxygen?

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