$n$ cadets have to stand in a row. If all possible permutations are equally likely, then the probability that two particular cadets stand side by side, is
$n$ cadets have to stand in a row. If all possible permutations are equally likely, then the probability that two particular cadets stand side by side, is
- A
$\frac{2}{n}$
- B
$\frac{1}{n}$
- C
$\frac{2}{{(n - 1)\,!}}$
- D
None of these
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