$n$ cadets have to stand in a row. If all possible permutations are equally likely,then the probability that two particular cadets stand side by side is

  • A
    $\frac{2}{n}$
  • B
    $\frac{1}{n}$
  • C
    $\frac{2}{(n - 1)!}$
  • D
    None of these

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