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(B) To evaluate the integral $\int 	an^2 x \, dx$,we use the trigonometric identity $	an^2 x = \sec^2 x - 1$.Substituting this into the integral,we

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$	an x - x + c$

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(B) To evaluate the integral $\int 	an^2 x \, dx$,we use the trigonometric identity $	an^2 x = \sec^2 x - 1$.Substituting this into the integral,we get:$\int 	an^2 x \, dx = \int (\sec^2 x - 1) \, dx$Using the linearity property of integration,we split the integral:$= \int \sec^2 x \, dx - \int 1 \, dx$We know that $\int \sec^2 x \, dx = 	an x$ and $\int 1 \, dx = x$.Therefore,the final result is $	an x - x + c$.

$\int \tan^2 x \, dx$ is equal to

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