frac{d}{dx}left[ frac{2}{pi }sin {x^circ} rig | vedclass

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(B) To find the derivative,first convert the angle from degrees to radians: $x^\circ = \frac{\pi x}{180} 	ext{ radians}$.Thus,the expression becomes:

Vedclass · Accepted Answer

$\frac{1}{90}\cos {x^\circ}$

Vedclass · Answer

(B) To find the derivative,first convert the angle from degrees to radians: $x^\circ = \frac{\pi x}{180} 	ext{ radians}$.Thus,the expression becomes: $\frac{d}{dx}\left[ \frac{2}{\pi }\sin \left( \frac{\pi x}{180} ight) ight]$.Using the chain rule,$\frac{d}{dx}\sin(ax) = a\cos(ax)$:$= \frac{2}{\pi } \cdot \frac{\pi }{180} \cos \left( \frac{\pi x}{180} ight)$.$= \frac{2}{180} \cos (x^\circ) = \frac{1}{90} \cos (x^\circ)$.

$\frac{d}{dx}\left[ \frac{2}{\pi }\sin {x^\circ} \right] = $

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