$A$ resistor is connected to a battery of $12 \text{ V}$ emf and internal resistance $2 \text{ }\Omega$. If the current in the circuit is $0.6 \text{ A}$,the terminal voltage of the battery is: (in $\text{ V}$)

What is the maximum number of $50 \, W - 100 \, V$ bulbs that can be connected in parallel to a battery of $120 \, V$ and $10 \, \Omega$ internal resistance so that they glow with maximum intensity?

In the circuit shown,the capacitance of the capacitor is $2\,\mu F$. Find the current flowing through the $2\,\Omega$ resistor in $A$.

As shown,the circuit is made of $8$ different resistors. It is found that when $R_1 = 4\,\,\Omega,$ the resistance between $A$ and $B$ is $2\,\,\Omega.$ Now replace $R_1$ by a $6\,\,\Omega$ resistor,what is the resistance between $A$ and $B$?

$A$ battery of internal resistance $4\,\Omega$ is connected to a network of resistors as shown in the figure. If maximum power is to be delivered to the network,the magnitude of $R$ in $\Omega$ should be:

Four resistances are connected in a circuit as shown in the given figure. The electric current flowing through a $4\, \Omega$ resistance and a $6\, \Omega$ resistance is respectively: