A submarine is designed to withstand an absol | vedclass

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(B) The formula for absolute pressure is $P = P_{atm} + ho g h$.
Here, $P = 100 	ext{ atm} = 100 	imes 10^5 	ext{ Pa}$, $P_{atm} = 1 	ext{ atm}

Vedclass · Accepted Answer

$990$

Vedclass · Answer

(B) The formula for absolute pressure is $P = P_{atm} + ho g h$.
Here, $P = 100 	ext{ atm} = 100 	imes 10^5 	ext{ Pa}$, $P_{atm} = 1 	ext{ atm} = 1 	imes 10^5 	ext{ Pa}$, $ho = 1000 	ext{ kg/m}^3$, and $g = 10 	ext{ m/s}^2$.
Substituting the values: $100 	imes 10^5 = 1 	imes 10^5 + (1000)(10)h$.
$100 	imes 10^5 - 1 	imes 10^5 = 10^4 h$.
$99 	imes 10^5 = 10^4 h$.
$h = \frac{99 	imes 10^5}{10^4} = 99 	imes 10 = 990 	ext{ m}$.
Thus, the submarine can go $990 	ext{ m}$ deep.

$A$ submarine is designed to withstand an absolute pressure of $100 \text{ atm}$. How deep can it go below the water surface (in $\text{ m}$)? (Consider the density of water = $1000 \text{ kg/m}^3$, $1 \text{ atm} = 1 \times 10^5 \text{ Pa}$, and gravitational acceleration $g = 10 \text{ m/s}^2$)

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