But-2-yne and hydrogen (one mole each) are se | vedclass

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(B) The hydrogenation of $But-2-yne$ with $Pd/C$ (Lindlar's catalyst or similar) gives $cis-But-2-ene$ $(X)$.The reduction of $But-2-yne$ with $Na / \

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$B$ and $D$ only

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(B) The hydrogenation of $But-2-yne$ with $Pd/C$ (Lindlar's catalyst or similar) gives $cis-But-2-ene$ $(X)$.The reduction of $But-2-yne$ with $Na / 	ext{liq. } NH_3$ (Birch reduction) gives $trans-But-2-ene$ $(Y)$.$A$. $X$ and $Y$ are geometric isomers (stereoisomers). This statement is correct.$B$. $X$ $(cis-But-2-ene)$ has a non-zero dipole moment due to the polarity of the $C-CH_3$ bonds. $Y$ $(trans-But-2-ene)$ has a dipole moment of zero. Thus,statement $B$ is incorrect.$C$. $cis-But-2-ene$ $(X)$ is more polar than $trans-But-2-ene$ $(Y)$,so $X$ has a higher boiling point than $Y$. This statement is correct.$D$. Both $X$ and $Y$ are isomers of $But-2-ene$. Ozonolysis of both $cis-But-2-ene$ and $trans-But-2-ene$ yields the same product,$acetaldehyde$ $(CH_3CHO)$. Thus,statement $D$ is incorrect.The incorrect statements are $B$ and $D$.

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