A mixed ether (P),when heated with excess of | vedclass

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(D) $1$. The mixed ether $(P)$ reacts with excess hot concentrated $HI$ to form two alkyl iodides. $2$. These alkyl iodides,upon treatment with aqueou

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(D) $1$. The mixed ether $(P)$ reacts with excess hot concentrated $HI$ to form two alkyl iodides. $2$. These alkyl iodides,upon treatment with aqueous $NaOH$,yield alcohols $(Q)$ and $(R)$. $3$. Both $(Q)$ and $(R)$ give a yellow precipitate with $NaOI$ (iodoform test),which implies both must contain a $CH_3CH(OH)-$ group or be ethanol $(CH_3CH_2OH)$. $4$. Ethyl sec-butyl ether $(CH_3CH_2-O-CH(CH_3)CH_2CH_3)$ on cleavage with $HI$ gives ethyl iodide $(CH_3CH_2I)$ and sec-butyl iodide $(CH_3CH(I)CH_2CH_3)$. $5$. Treatment with $NaOH$ converts these to ethanol $(CH_3CH_2OH)$ and sec-butanol $(CH_3CH(OH)CH_2CH_3)$. $6$. Both ethanol and sec-butanol give a positive iodoform test with $NaOI$ (forming yellow $CHI_3$ precipitate). $7$. Thus,the ether $(P)$ is ethyl sec-butyl ether.

$A$ mixed ether $(P)$,when heated with excess of hot concentrated hydrogen iodide,produces two different alkyl iodides which when treated with aqueous $NaOH$ give compounds $(Q)$ and $(R)$. Both $(Q)$ and $(R)$ give a yellow precipitate with $NaOI$. Identify the mixed ether $(P)$:

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