$A$ boy throws a ball into the air at $45^{\circ}$ from the horizontal to land it on the roof of a building of height $H$. If the ball attains maximum height in $2 \text{ s}$ and lands on the building in $3 \text{ s}$ after launch,then the value of $H$ is . . . . . . $\text{m}$. $(g = 10 \text{ m/s}^2)$
- A$20$
- B$10$
- C$25$
- D$15$
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In the projectile motion of a particle on a level ground,which of the following remains constant with reference to time and position?
Two projectiles are thrown with the same initial velocity making an angle of $45^{\circ}$ and $30^{\circ}$ with the horizontal,respectively. The ratio of their respective ranges will be:
On a planet,a particle is thrown with a velocity $\vec{V} = 6 \hat{i} + (20 - 4t) \hat{j}$. Match the lists. (All quantities are in $SI$ units)
$P$. Time of flight $1$. $3$ $Q$. Time when particle is moving at an angle of $53^{\circ}$ with horizontal in upwards direction. $2$. $10$ $R$. Range of the particle $3$. $50$ $S$. Maximum height reached by the particle $4$. $60$
| $P$. Time of flight | $1$. $3$ |
| $Q$. Time when particle is moving at an angle of $53^{\circ}$ with horizontal in upwards direction. | $2$. $10$ |
| $R$. Range of the particle | $3$. $50$ |
| $S$. Maximum height reached by the particle | $4$. $60$ |
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View Solution$A$ body when projected at an angle $\theta$ with the horizontal reaches a maximum height $H$. The time of flight of the body will be ($g=$ acceleration due to gravity).
$A$ ball is projected from the ground into the air. At a height of $5 \text{ m}$, its velocity is $\vec{v} = (5 \hat{i} + 5 \hat{j}) \text{ m s}^{-1}$. The maximum height reached by the ball is (Acceleration due to gravity $g = 10 \text{ m s}^{-2}$): (in $\text{ m}$)
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