A given quantity of gas is taken from A to C | vedclass

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(C) According to the First Law of Thermodynamics,$\Delta Q = \Delta U + \Delta W$,where $\Delta U$ is the change in internal energy.Since internal ene

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$160 \ J$

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(C) According to the First Law of Thermodynamics,$\Delta Q = \Delta U + \Delta W$,where $\Delta U$ is the change in internal energy.Since internal energy is a state function,$\Delta U$ is the same for any path between the same two states $A$ and $C$.For the direct path $A \rightarrow C$:$\Delta W_{AC} = 200 \ J$$\Delta Q_{AC} = 280 \ J$$\Delta U = \Delta Q_{AC} - \Delta W_{AC} = 280 \ J - 200 \ J = 80 \ J$.For the path $A \rightarrow B \rightarrow C$:$\Delta W_{ABC} = 80 \ J$Since $\Delta U$ is a state function,$\Delta U = 80 \ J$ for this path as well.Therefore,the heat absorbed $\Delta Q_{ABC} = \Delta U + \Delta W_{ABC} = 80 \ J + 80 \ J = 160 \ J$.

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