N_2H_4 and H_2O_2 show similarity in | vedclass

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(D) In $N_2H_4$ (hydrazine),each nitrogen atom is bonded to two hydrogen atoms and one nitrogen atom,with one lone pair. The steric number for each $N

Vedclass · Accepted Answer

Hybridisation of central atoms

Vedclass · Answer

(D) In $N_2H_4$ (hydrazine),each nitrogen atom is bonded to two hydrogen atoms and one nitrogen atom,with one lone pair. The steric number for each $N$ atom is $3 + 1 = 4$,which corresponds to $sp^3$ hybridisation.In $H_2O_2$ (hydrogen peroxide),each oxygen atom is bonded to one hydrogen atom and one oxygen atom,with two lone pairs. The steric number for each $O$ atom is $2 + 2 = 4$,which corresponds to $sp^3$ hybridisation.Therefore,both compounds show similarity in the hybridisation of their central atoms $(sp^3)$.

$N_2H_4$ and $H_2O_2$ show similarity in

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