$A$ galvanometer can be converted to a voltmeter of full-scale deflection $V_{0}$ by connecting a series resistance $R_{1}$ and can be converted to an ammeter of full-scale deflection $I_{0}$ by connecting a shunt resistance $R_{2}$. What is the current flowing through the galvanometer at its full-scale deflection?

  • A
    $\frac{V_{0}-I_{0} R_{2}}{R_{1}-R_{2}}$
  • B
    $\frac{V_{0}+I_{0} R_{2}}{R_{1}+R_{2}}$
  • C
    $\frac{V_{0}-I_{0} R_{2}}{R_{2}-R_{1}}$
  • D
    $\frac{V_{0}+I_{0} R_{1}}{R_{1}+R_{2}}$

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Similar Questions

Why does a galvanometer not show full-scale deflection after connecting it in a circuit?

Which of the following statements is correct?

$A$ galvanometer of resistance $36 \ \Omega$ is converted into an ammeter by using a shunt of $4 \ \Omega$. The fraction $f_0$ of the total current passing through the galvanometer is:

In an experiment to find the resistance of a galvanometer by the half-deflection method, a $5 V$ battery and a high resistance of $4.9 k\Omega$ are connected in the circuit. In the absence of any shunt resistance, the galvanometer reads $20$ divisions when current flows in the circuit. To reduce the deflection by half, the value of the shunt resistance used is $98 \Omega$. The figure of merit of the galvanometer is given as $..... \mu A / \text{division}$.

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$A$ galvanometer coil has a resistance of $990 \,\Omega$. It shows a full-scale deflection for a current of $10 \,mA$. Calculate the value of the shunt resistance required to convert it into an ammeter of range $1 \,A$.

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