A quantity X is given by varepsilon_0 L frac{ | vedclass

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(D) The expression is $X = \varepsilon_0 L \frac{\Delta V}{\Delta t}$.We know that the electric flux $\phi_E = E \cdot A$,where $E = \frac{V}{L}$ and

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(D) The expression is $X = \varepsilon_0 L \frac{\Delta V}{\Delta t}$.We know that the electric flux $\phi_E = E \cdot A$,where $E = \frac{V}{L}$ and $A = L^2$.Thus,$\phi_E = \frac{V}{L} \cdot L^2 = V \cdot L$.Substituting this into the expression for $X$,we get $X = \varepsilon_0 \frac{\Delta \phi_E}{\Delta t}$.According to the definition of displacement current $i_d = \varepsilon_0 \frac{d\phi_E}{dt}$,the quantity $X$ represents the displacement current.Therefore,the dimension of $X$ is the same as that of current.

$A$ quantity $X$ is given by $\varepsilon_0 L \frac{\Delta V}{\Delta t}$,where $\varepsilon_0$ is the permittivity of free space,$L$ is the length,$\Delta V$ is a potential difference,and $\Delta t$ is a time interval. The dimension of $X$ is the same as that of

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