_{98}Cf^{246} was formed along with a neutron | vedclass

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(C) Let the unknown substance be $_{Z}X^{A}$.The nuclear reaction is: $_{Z}X^{A} + _{6}C^{12} \rightarrow _{98}Cf^{246} + _{0}n^{1}$.According to the

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$_{92}U^{235}$

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(C) Let the unknown substance be $_{Z}X^{A}$.The nuclear reaction is: $_{Z}X^{A} + _{6}C^{12} \rightarrow _{98}Cf^{246} + _{0}n^{1}$.According to the law of conservation of mass number: $A + 12 = 246 + 1$,which gives $A = 235$.According to the law of conservation of atomic number: $Z + 6 = 98$,which gives $Z = 92$.The element with atomic number $92$ is Uranium $(U)$.Therefore,the unknown substance is $_{92}U^{235}$.

$_{98}Cf^{246}$ was formed along with a neutron when an unknown radioactive substance was bombarded with $_{6}C^{12}$. The unknown substance was:

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