m_{1} and m_{2} are two bodies of masses sepa | vedclass

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(A) Let the mass $m_{1}$ be placed at the origin $(0, 0)$ and the mass $m_{2}$ be placed at a distance $R$ along the x-axis at $(R, 0)$.The formula fo

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$\frac{m_{2} R}{m_{1}+m_{2}}$

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(A) Let the mass $m_{1}$ be placed at the origin $(0, 0)$ and the mass $m_{2}$ be placed at a distance $R$ along the x-axis at $(R, 0)$.The formula for the x-coordinate of the centre of mass is given by:$X_{cm} = \frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}}$Substituting the values $x_{1} = 0$ and $x_{2} = R$:$X_{cm} = \frac{m_{1} 	imes 0 + m_{2} 	imes R}{m_{1} + m_{2}}$$X_{cm} = \frac{m_{2} R}{m_{1} + m_{2}}$Thus,the distance of the centre of mass from $m_{1}$ is $\frac{m_{2} R}{m_{1} + m_{2}}$.

$m_{1}$ and $m_{2}$ are two bodies of masses separated by a distance $R$. The distance of the centre of mass of the bodies from the mass $m_{1}$ is

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