$A$ constant force of $5 N$ accelerates a stationary particle of mass $500 g$ through a displacement of $5 m$. The average power delivered is: (in $W$)

$A$ body of mass $0.5 \ kg$ is supplied with a power $P$ (in watt) which varies with time $t$ (in second) as $P = 3t^2 + 3$. If the velocity of the body at time $t = 0$ is zero,then the velocity of the body at time $t = 3 \ s$ is (in $ms^{-1}$)

$A$ body of mass $4 \,kg$ is moving with momentum of $8 \,kg \,m/s$. $A$ force of $0.2 \,N$ acts on it in the direction of motion of the body for $10 \,s$. The increase in kinetic energy in joules is

$A$ body of mass $500 \ g$ is falling from rest from a height of $3.2 \ m$ from the ground. If the body reaches the ground with a velocity of $6 \ ms^{-1}$, then the energy lost by the body due to air resistance is (Acceleration due to gravity $= 10 \ ms^{-2}$) (in $J$)

Two particles of equal mass start moving in opposite directions from point $A$ in a horizontal circular path. Their tangential velocities are $v$ and $2v$ respectively,as shown in the figure. At the time of collision,the particles move with the same speed. How many elastic collisions must occur after the first one so that these two particles reach point $A$ again?

$A$ bullet of mass $10\, g$ moving horizontally with a velocity of $400\, m s^{-1}$ strikes a wood block of mass $2\, kg$ which is suspended by a light inextensible string of length $5\, m$. As a result,the centre of gravity of the block is found to rise a vertical distance of $10\, cm$. The speed of the bullet after it emerges out horizontally from the block will be ................... $m s^{-1}$.