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(D) According to Stefan-Boltzmann law,the power $P$ radiated by a black body of surface area $A$ at absolute temperature $T$ is given by $P = \sigma A

Vedclass · Accepted Answer

$11.34$

Vedclass · Answer

(D) According to Stefan-Boltzmann law,the power $P$ radiated by a black body of surface area $A$ at absolute temperature $T$ is given by $P = \sigma A T^4$.Given values:$\sigma = 5.67 	imes 10^{-8} \ W m^{-2} K^{-4}$$T = 727^{\circ} C = 727 + 273 = 1000 \ K$$A = 200 \ mm^2 = 200 	imes 10^{-6} \ m^2$Substituting these values into the formula:$P = (5.67 	imes 10^{-8}) 	imes (200 	imes 10^{-6}) 	imes (1000)^4$$P = 5.67 	imes 10^{-8} 	imes 200 	imes 10^{-6} 	imes 10^{12}$$P = 5.67 	imes 2 	imes 10^2 	imes 10^{-14} 	imes 10^{12}$$P = 11.34 	imes 10^2 	imes 10^{-2}$$P = 11.34 \ J/s$.

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