Fe(OH)_3 is a positively charged sol. For its | vedclass

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(D) $Fe(OH)_3$ is a positively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the

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$Na_3[Fe(CN)_6]$

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(D) $Fe(OH)_3$ is a positively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the ion carrying a charge opposite to that of the colloidal particles.Since $Fe(OH)_3$ is positively charged,it requires an anion for coagulation.The given electrolytes dissociate as follows:$Na_2SO_4 ightarrow 2Na^+ + SO_4^{2-}$$Na_3[Fe(CN)_6] ightarrow 3Na^+ + [Fe(CN)_6]^{3-}$$Cr(OH)_3$ and $Al(OH)_3$ are insoluble hydroxides and do not act as effective coagulating agents in this context.Comparing the valency of the anions,$[Fe(CN)_6]^{3-}$ has a valency of $3$,while $SO_4^{2-}$ has a valency of $2$.According to the Hardy-Schulze rule,the higher the valency of the coagulating ion,the greater is its coagulating power.Therefore,$[Fe(CN)_6]^{3-}$ is the most effective coagulating agent among the given options.Flocculation value = $\frac{1}{	ext{Coagulating power}}$. Since $[Fe(CN)_6]^{3-}$ has the highest coagulating power,it has the lowest flocculation value,making it the best precipitating agent.

$Fe(OH)_3$ is a positively charged sol. For its precipitation,the best precipitating agent is:

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