X litres of carbon monoxide is present at STP | vedclass

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(B) The balanced chemical equation for the oxidation of carbon monoxide is:$CO(g) + \frac{1}{2} O_2(g) \longrightarrow CO_2(g)$According to Avogadro's

Vedclass · Accepted Answer

$11.207$

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(B) The balanced chemical equation for the oxidation of carbon monoxide is:$CO(g) + \frac{1}{2} O_2(g) \longrightarrow CO_2(g)$According to Avogadro's Law,at constant temperature and pressure,the volume of gases is directly proportional to their moles.From the stoichiometry of the reaction,$1$ mole of $CO$ produces $1$ mole of $CO_2$.Therefore,$1$ volume of $CO$ produces $1$ volume of $CO_2$ at $STP$.Given that $11.207$ litres of $CO_2$ is formed,the volume of $CO$ required is also $11.207$ litres.Thus,$X = 11.207$.

$X$ litres of carbon monoxide is present at $STP$. It is completely oxidized to $CO_2$. The volume of $CO_2$ formed is $11.207$ litres. What is the value of $X$ in litres?

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